Hi all,

As discuss in the topic "Designing dice for dice snobs", I designed today a new

Average D6 where you have to make the average of 4 faces of an octahedron, to find the result of a regular D6.

The faces of the octahedron are numbered 1, 1, 1, 1, 2, 4, 8, and 10.

Here are the operations :

(1 + 1 + 1 + 1)/4 = 4/4 = 1

(1 + 1 + 2 + 4)/4 = 8/4 = 2

(1 + 1 + 2 + 8)/4 =12/4 = 3

(1 + 1 + 4 +10)/4 =16/4 = 4

(1 + 1 + 8 +10)/4 =20/4 = 5

(2 + 4 + 8 +10)/4 =24/4 = 6
The positions of the virtual 1, 2, 3, 4, 5 and 6 are the regular positions of a D6 (opposite sides sum to 7).

This die is 21.5 x 21.5 x 21.5 mm. The diameter of the wire of the frame is 3 mm so you can print it in Stainless Steel. The price will be less than $25.

It has not been prototyped yet (as soon as I will do, it will be in the "It arrived" section).

More informations soon about other variations of this design.

[EDIT]

if you choose 1, 1, 1, 1 for the four upper faces of the octahedon, you still have several choices for the lower faces (all numbers being larger or equal to 1):

- 1, 5, 9, 9 (all numbers are in the form 4k+1, but I did not choose this one because 1 is repeated again and 9 appears twice)

- 2, 4, 10, 8 (opposite numbers sum to 12, the one I chosed)

- 3, 3, 11, 7 (all numbers are in the form 4k+3 unlike the four 1 of the opposite faces, I did not chose this one also because 3 appears twice)

- 4, 2, 12, 6 (I prefered the other one because the maximum number is smaller)

- 5, 1, 13, 5 (all numbers are in the form 4k+1, I did not choose this one because 1 is repeated again and 5 appears twice)