This is the set of 14 Planar Tetrarhons. This is HALF of the 28 Tetrarhons. And the Tetrarhons are a subset of the Polyrhons (Poly Rhombic Dodecahedra). The 28 Tetrarhons are all possible ways of connecting 4 Rhombic Dodecahedra. For this set, we will limit ourselves to the 14 Planar Tetrarhons (those that can lay flat in one layer either hexagonally or squarely). Note the total volume of this set is 56 units (4×14). Can this set form a size 6 Tetrahedron? The answer is YES!!
Can you find a solution?